Glenbrook and Springbrook are at each end of a railroad track 100 miles long. At exactly the same instant, one train leaves Glenbrook and one leaves Spingbrook. The engineer operating the train from Glenbrook averages 50 miles an hour, while the engineer on the train from Springbrook averages 40 mile an hour. Where will they meet?
This is a Mathematical trick, there is always a gap so in that sense they never meet each other!
Physically that would be impossible so they would meet at Cedarbrook which is approximately 55-56 miles from Glenbrook.